Add *Tree.SetPositionPath (#426)

Signed-off-by: Stephen Levine <stephen.levine@gmail.com>
This commit is contained in:
Stephen Levine
2020-07-31 23:44:50 -04:00
committed by GitHub
parent 34de94e6a8
commit 661484ae7e
+44
View File
@@ -213,6 +213,50 @@ func (t *Tree) GetPosition(key string) Position {
return t.GetPositionPath(strings.Split(key, "."))
}
// SetPositionPath sets the position of element in the tree indicated by 'keys'.
// If keys is of length zero, the current tree position is set.
func (t *Tree) SetPositionPath(keys []string, pos Position) {
if len(keys) == 0 {
t.position = pos
return
}
subtree := t
for _, intermediateKey := range keys[:len(keys)-1] {
value, exists := subtree.values[intermediateKey]
if !exists {
return
}
switch node := value.(type) {
case *Tree:
subtree = node
case []*Tree:
// go to most recent element
if len(node) == 0 {
return
}
subtree = node[len(node)-1]
default:
return
}
}
// branch based on final node type
switch node := subtree.values[keys[len(keys)-1]].(type) {
case *tomlValue:
node.position = pos
return
case *Tree:
node.position = pos
return
case []*Tree:
// go to most recent element
if len(node) == 0 {
return
}
node[len(node)-1].position = pos
return
}
}
// GetPositionPath returns the element in the tree indicated by 'keys'.
// If keys is of length zero, the current tree is returned.
func (t *Tree) GetPositionPath(keys []string) Position {